Criteria criteria = session.createCriteria(User.class); // 查询user所有字段 List users = criteria.list(); Iterator iterator = users.iterator(); System.out.println("id \t name/age"); while(iterator.hasNext()) { User user = (User) iterator.next(); System.out.println(user.getId() + " \t " + user.getName() + "/" + user.getAge()); }Hibernate实际上使用以下的SQL来查询数据库:
select this_.id as id0_, this_.name as name0_0_, this_.age as age0_0_ from user this_Criteria实际上只是个容器,如果想要设定查询条件,则要使用add()方法加入Restrictions的条件限制,例如查询age大于20且小于40的数据:
Criteria criteria = session.createCriteria(User.class); criteria.add(Restrictions.gt("age", new Integer(20))); criteria.add(Restrictions.lt("age", new Integer(40))); List users = criteria.list();您也可以使用逻辑组合来进行查询,例如结合age等于(eq)20或(or)age为空(isNull)的条件:
Criteria criteria = session.createCriteria(User.class); criteria.add(Restrictions.or( Restrictions.eq("age", new Integer(20)), Restrictions.isNull("age") )); List users = criteria.list();也可以使用sqlRestriction()方法来提供SQL语法作限定查询,例如查询name以cater开头的数据:
Criteria criteria = session.createCriteria(User.class); criteria.add(Restrictions.sqlRestriction("{alias}.name LIKE (?)", "cater%", Hibernate.STRING)); List users = criteria.list();其中alias将被替换为与User类别相关的名称,而?将被替换为cater%,也就是第二个参数所提供的值,在SQL撰写时,不必再写WHERE,如果有多个查询条件,例如BETWEEN子句的查询,则可以如下:
Criteria criteria = session.createCriteria(User.class); Integer[] ages = {new Integer(20), new Integer(40)}; Type[] types = {Hibernate.INTEGER, Hibernate.INTEGER}; criteria.add(Restrictions.sqlRestriction("{alias}.age BETWEEN (?) AND (?)", ages, types)); List users = criteria.list();Restrictions的几个常用限定查询方法如下表所示:
方法 | 说明 |
Restrictions.eq | 等于 |
Restrictions.allEq | 使用Map,使用key/value进行多个等于的比对 |
Restrictions.gt | 大于 > |
Restrictions.ge | 大于等于 >= |
Restrictions.lt | 小于 < |
Restrictions.le | 小于等于 <= |
Restrictions.between | 对应SQL的BETWEEN子句 |
Restrictions.like | 对应SQL的LIKE子句 |
Restrictions.in | 对应SQL的in子句 |
Restrictions.and | and关系 |
Restrictions.or | or关系 |
Restrictions.sqlRestriction | SQL限定查询 |